KMP
Chivas-Regal
#
# CodeForces1200E_CompressWords
# 🔗
https://codeforces.com/problemset/problem/1200/E
# 💡
题目意思是，每次合并 res 和当前字符串 s
我们在合并时有可能会删去字符串，但是删去的长度不会超过s
所以我们在匹配时只需要匹配不超过vec[i]长度的res与vec[i]的公共前后缀
# ✅
/*
________ _ ________ _
/ ______| | | | __ | | |
/ / | | | |__| | | |
| | | |___ _ _ _ ___ _ _____ | ___| ______ _____ ___ _ | |
| | | __ \ |_| | | | | | _\| | | ____| | |\ \ | __ | | _ | | _\| | | |
| | | | \ | _ | | | | | | \ | | \___ | | \ \ | |_/ _| | |_| | | | \ | | |
\ \______ | | | | | | \ |_| / | |_/ | ___/ | | | \ \ | /_ \__ | | |_/ | | |
Author : \________| |_| |_| |_| \___/ |___/|_| |_____| _________|__| \__\ |______| | | |___/|_| |_|
____| |
\_____/
*/
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <utility>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define EPS 1e-6
#define PI acos(-1.0)
#define INF 0x7FFFFFFF
#define ll long long
#define ull unsigned long long
#define INT __int128
#define LOWBIT(x) ((x) & (-x))
#define LOWBD(a, x) lower_bound(a.begin(), a.end(), x) - a.begin()
#define UPPBD(a, x) upper_bound(a.begin(), a.end(), x) - a.begin()
#define TEST(a) cout << "---------" << a << "---------" << endl
#define CHIVAS_ inline int MAIN()
#define _REGAL return 0;
#define SP system("pause")
#define IOS ios::sync_with_stdio(false)
//#define map unordered_map
#define pbb pair<bool, bool>
#define pii pair<int, int>
#define pll pair<ll, ll>
#define PB(x) push_back(x)
#define ALL(a) a.begin(),a.end()
#define MEM(a, b) memset(a, b, sizeof(a))
#define EACH_CASE(cass) for (cass = inputInt(); cass; cass--)
#define LS l, mid, rt << 1
#define RS mid + 1, r, rt << 1 | 1
#define GETMID (l + r) >> 1
using namespace std;
inline int inputInt(){int X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1);}
inline void outInt(int X){if(X<0) {putchar('-'); X=~(X-1);}int s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
inline ll inputLL(){ll X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1); }
inline void outLL(ll X){if(X<0) {putchar('-'); X=~(X-1);}ll s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
template<typename T> inline T MAX(T a, T b){return a > b? a : b;}
template<typename T> inline T MIN(T a, T b){return a > b? b : a;}
template<typename T> inline void SWAP(T &a, T &b){T tp = a; a = b; b = tp;}
template<typename T> inline T GCD(T a, T b){return b > 0? GCD(b, a % b) : a;}
template<typename T> inline void ADD_TO_VEC_int(T &n, vector<T> &vec){vec.clear(); cin >> n; for(int i = 0; i < n; i ++){T x; cin >> x, vec.PB(x);}}
template<typename T> inline pair<T, T> MaxInVector_ll(vector<T> vec){T MaxVal = -LNF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_ll(vector<T> vec){T MinVal = LNF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<T, T> MaxInVector_int(vector<T> vec){T MaxVal = -INF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_int(vector<T> vec){T MinVal = INF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<map<T, T>, vector<T> > DIV(T n){T nn = n;map<T, T> cnt;vector<T> div;for(ll i = 2; i * i <= nn; i ++){while(n % i == 0){if(!cnt[i]) div.push_back(i);cnt[i] ++;n /= i;}}if(n != 1){if(!cnt[n]) div.push_back(n);cnt[n] ++;n /= n;}return make_pair(cnt, div);}
namespace Solution_In_Codeforces{
inline void solve();
namespace N_cass {
void Main(){ int cass; for ( cin >> cass; cass; cass -- ) { solve();} };
}
namespace One_cass {
void Main(){ solve(); };
}
}
inline void Solution_In_Codeforces::solve() {}
inline void Get_next ( int *nxt, string s ) { // 自获取nxt数组
nxt[0] = -1;
for ( int i = 0, j = -1; i < s.size(); i ++ ) {
while ( j >= 0 && s[i + 1] != s[j + 1] ) j = nxt[j];
if ( s[i + 1] == s[j + 1] ) j ++;
nxt[i + 1] = j;
}
}
inline int KMP ( string a, string b ) { // kmp前后缀匹配
int nxt[b.size() + 10];
int res;
Get_next(nxt, b);
for ( int i = -1, j = -1; i + 1 < a.size(); i ++ ) {
while ( j >= 0 && b[j + 1] != a[i + 1] ) j = nxt[j];
if ( b[j + 1] == a[i + 1] ) j ++;
if ( i + 1 == a.size() - 1 ) res = j;
if ( j + 1 == b.size() ) j = nxt[j];
}return res + 1;
}
CHIVAS_{
int n; cin >> n;
vector<string> vec;
for ( int i = 0; i < n; i ++ ) {
string s; cin >> s;
vec.push_back(s);
}
string res = vec[0];
for ( int i = 1; i < n; i ++ ) {
int las = MIN(res.size(), vec[i].size() + 1); // res后面用来匹配vec[i]的长度
string a = res.substr(res.size() - las, las); // res后面用来匹配vec[i]的字符串
int com = KMP(a, vec[i]); // a 与 vec[i] 匹配后得到的要删去字符的数量
res += vec[i].substr(com, vec[i].size() - com + 1); // res 加上这次匹配的字符
} cout << res << endl;
_REGAL;
}
int main(){
#ifndef ONLINE_JUDGE
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
MAIN();
#ifndef ONLINE_JUDGE
cerr << "\033[1m\033[31m\n"
<< "\n\n===============================\n"
<< "|| Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s. ||\n"
<< "==============================="
<< "\033[0m";
#endif
exit(0);
}
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# HDU1686_Oulipo
# 🔗
https://acm.hdu.edu.cn/showproblem.php?pid=1686
# 💡
由于这里每匹配上一次后可以重复匹配
所以在匹配到最后计数完成后，副串不用回到-1，只需要回溯一次nxt即可
# ✅
/*
________ _ ________ _
/ ______| | | | __ | | |
/ / | | | |__| | | |
| | | |___ _ _ _ ___ _ _____ | ___| ______ _____ ___ _ | |
| | | __ \ |_| | | | | | _\| | | ____| | |\ \ | __ | | _ | | _\| | | |
| | | | \ | _ | | | | | | \ | | \___ | | \ \ | |_/ _| | |_| | | | \ | | |
\ \______ | | | | | | \ |_| / | |_/ | ___/ | | | \ \ | /_ \__ | | |_/ | | |
Author : \________| |_| |_| |_| \___/ |___/|_| |_____| _________|__| \__\ |______| | | |___/|_| |_|
____| |
\_____/
*/
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <utility>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define EPS 1e-6
#define PI acos(-1.0)
#define INF 0x7FFFFFFF
#define ll long long
#define ull unsigned long long
#define INT __int128
#define LOWBIT(x) ((x) & (-x))
#define LOWBD(a, x) lower_bound(a.begin(), a.end(), x) - a.begin()
#define UPPBD(a, x) upper_bound(a.begin(), a.end(), x) - a.begin()
#define TEST(a) cout << "---------" << a << "---------" << endl
#define CHIVAS_ int main()
#define _REGAL exit(0)
#define SP system("pause")
#define IOS ios::sync_with_stdio(false)
//#define map unordered_map
#define pii pair<int, int>
#define pll pair<ll, ll>
#define PB(x) push_back(x)
#define ALL(a) a.begin(),a.end()
#define MEM(a, b) memset(a, b, sizeof(a))
#define EACH_CASE(cass) for (cass = inputInt(); cass; cass--)
#define LS l, mid, rt << 1
#define RS mid + 1, r, rt << 1 | 1
#define GETMID (l + r) >> 1
using namespace std;
inline int inputInt(){int X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1);}
inline void outInt(int X){if(X<0) {putchar('-'); X=~(X-1);}int s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
inline ll inputLL(){ll X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1); }
inline void outLL(ll X){if(X<0) {putchar('-'); X=~(X-1);}ll s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
template<typename T> inline T MAX(T a, T b){return a > b? a : b;}
template<typename T> inline T MIN(T a, T b){return a > b? b : a;}
template<typename T> inline void SWAP(T &a, T &b){T tp = a; a = b; b = tp;}
template<typename T> inline T GCD(T a, T b){return b > 0? GCD(b, a % b) : a;}
template<typename T> inline void ADD_TO_VEC_int(T &n, vector<T> &vec){vec.clear(); cin >> n; for(int i = 0; i < n; i ++){T x; cin >> x, vec.PB(x);}}
template<typename T> inline pair<T, T> MaxInVector_ll(vector<T> vec){T MaxVal = -LNF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_ll(vector<T> vec){T MinVal = LNF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<T, T> MaxInVector_int(vector<T> vec){T MaxVal = -INF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_int(vector<T> vec){T MinVal = INF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<map<T, T>, vector<T> > DIV(T n){T nn = n;map<T, T> cnt;vector<T> div;for(ll i = 2; i * i <= nn; i ++){while(n % i == 0){if(!cnt[i]) div.push_back(i);cnt[i] ++;n /= i;}}if(n != 1){if(!cnt[n]) div.push_back(n);cnt[n] ++;n /= n;}return make_pair(cnt, div);}
namespace Solution_In_Codeforces{
inline void solve();
namespace N_cass {
int Main(){ int cass; for ( cin >> cass; cass; cass -- ) { solve();} return 0;};
}
namespace One_cass {
int Main(){ solve(); return 0;};
}
}
inline void Solution_In_Codeforces::solve(){};
const int N = 1e6 + 10;
class KMP_node{
private:
string a, b;
int nxt[N];
public:
inline KMP_node ( string aa, string bb ) {
a = aa;
b = bb;
}
inline void Get_Next ( ) {
for ( int i = 0; i < N; i ++ ) nxt[i] = -1;
int j = -1, m = b.size();
for ( int i = 0; i + 1 < m; i ++ ) {
while ( j >= 0 && b[i + 1] != b[j + 1] ) j = nxt[j];
if ( b[i + 1] == b[j + 1] ) j ++;
nxt[i + 1] = j;
}
}
inline int KMP ( ) {
int n = a.size(), m = b.size();
int j = -1, res = 0;
for ( int i = -1; i + 1 < n; i ++ ) {
while ( j >= 0 && a[i + 1] != b[j + 1] ) j = nxt[j];
if ( a[i + 1] == b[j + 1]) j ++;
if ( j == m - 1 ) {
res ++;
j = nxt[j];
}
}
return res;
}
};
string sa, sb;
inline void Main(){IOS;
int cass;
for ( cin >> cass; cass; cass -- ){
cin >> sa >> sb;
KMP_node kmp = KMP_node(sb, sa);
kmp.Get_Next();
cout << kmp.KMP() << endl;
}
}
int main(){
#ifndef ONLINE_JUDGE
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
Main();
#ifndef ONLINE_JUDGE
cerr << "\033[1m\033[31m" << "\n\n===============================\n" << "|| Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s. ||\n" << "===============================" << "\033[0m";
#endif
return 0;
}
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# HDU2087_剪花布条
# 🔗
http://acm.hdu.edu.cn/showproblem.php?pid=2087
# 💡
KMP模板
但是不能重复
所以一旦判成一次j要变-1
# ✅
#pragma region
#pragma GCC optimize(3,"Ofast","inline")
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define eps 1e-6
#define PI acos(-1.0)
#define ll long long
#define INF 0x7FFFFFFF
#define Regal exit(0)
#define Chivas int main()
#define pb(x) push_back(x)
#define SP system("pause")
#define Max(a,b) ((a)>(b)?(a):(b))
#define Min(a,b) ((a)<(b)?(a):(b))
#define IOS ios::sync_with_stdio(false)
#define mm(a, b) memset(a, b, sizeof(a))
#define each_cass(cass) for (cin>>cass; cass; cass--)
#define test(a) cout << "---------" << a << "---------" << '\n'
using namespace std;
#pragma endregion
//全局变量
#pragma region
struct node_KMP{
string a, b;
int nxt[1010];
inline void GetNext(){//模式串自己和自己匹配的过程
int len = b.size();
for(int i = 0; i < len; i ++) nxt[i] = -1;//初始化nxt
int j = -1;//i和j要错一位，不然都相等了
for(int i = 0; i < len - 1; i ++){
while(j >= 0 && b[j + 1] != b[i + 1]) j = nxt[j];//j要向前拉
if(b[i + 1] == b[j + 1]) j ++;//都匹配j可以++
nxt[i + 1] = j;//记录每个点的nxt值，因为判就按下一位判的，所以每次存的都是下一位的nxt
}
}
inline int KMP(){//a和b匹配的过程
int lenb = b.size();
int lena = a.size();
int j = -1;
int cnt = 0;
for(int i = -1; i < lena - 1; i ++){
while(j >= 0 && b[j + 1] != a[i + 1]) j = nxt[j];//向前拉
if(b[j + 1] == a[i + 1]) j ++;
if(j == lenb - 1){//因为判都是按下一位判的，所以j的下一位到头了就是成功了
cnt ++;
j = -1;//前面的裁掉了，要重新开始了
}
}
return cnt;
}
};
#pragma endregion
//主体------------------------------------------
Chivas{
string a, b;
node_KMP nd;
IOS;
while(cin >> a, a != "#"){
cin >> b;
nd.a = a, nd.b = b;
nd.GetNext();
cout << nd.KMP() << endl;
}
Regal;
}
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# HDU2594_Simpson'sHiddenTalents
# 🔗
http://acm.hdu.edu.cn/showproblem.php?pid=2594
# 💡
把两个串拼在一起
求总串的nxt值但不能超过两个串的最小长度
这里就算一下a的nxt值
然后KMP中b和a向后走
b的后面和a的nxt含的长度匹配
若b走到尾时看一下a的j在哪，就是b的后缀中a的前缀匹配的长度
# ✅
/*
________ _ ________ _
/ ______| | | | __ | | |
/ / | | | |__| | | |
| | | |___ _ _ _ ___ _ _____ | ___| ______ _____ ___ _ | |
| | | __ \ |_| | | | | | _\| | | ____| | |\ \ | __ | | _ | | _\| | | |
| | | | \ | _ | | | | | | \ | | \___ | | \ \ | |_/ _| | |_| | | | \ | | |
\ \______ | | | | | | \ |_| / | |_/ | ___/ | | | \ \ | /_ \__ | | |_/ | | |
Author : \________| |_| |_| |_| \___/ |___/|_| |_____| _________|__| \__\ |______| | | |___/|_| |_|
____| |
\_____/
*/
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <utility>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define EPS 1e-6
#define PI acos(-1.0)
#define INF 0x7FFFFFFF
#define ll long long
#define ull unsigned long long
#define INT __int128
#define LOWBIT(x) ((x) & (-x))
#define LOWBD(a, x) lower_bound(a.begin(), a.end(), x) - a.begin()
#define UPPBD(a, x) upper_bound(a.begin(), a.end(), x) - a.begin()
#define TEST(a) cout << "---------" << a << "---------" << endl
#define CHIVAS_ inline int Main()
#define _REGAL return 0;
#define SP system("pause")
#define IOS ios::sync_with_stdio(false)
//#define map unordered_map
#define pii pair<int, int>
#define pll pair<ll, ll>
#define PB(x) push_back(x)
#define ALL(a) a.begin(),a.end()
#define MEM(a, b) memset(a, b, sizeof(a))
#define EACH_CASE(cass) for (cass = inputInt(); cass; cass--)
#define LS l, mid, rt << 1
#define RS mid + 1, r, rt << 1 | 1
#define GETMID (l + r) >> 1
using namespace std;
inline int inputInt(){int X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1);}
inline void outInt(int X){if(X<0) {putchar('-'); X=~(X-1);}int s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
inline ll inputLL(){ll X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1); }
inline void outLL(ll X){if(X<0) {putchar('-'); X=~(X-1);}ll s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
template<typename T> inline T MAX(T a, T b){return a > b? a : b;}
template<typename T> inline T MIN(T a, T b){return a > b? b : a;}
template<typename T> inline void SWAP(T &a, T &b){T tp = a; a = b; b = tp;}
template<typename T> inline T GCD(T a, T b){return b > 0? GCD(b, a % b) : a;}
template<typename T> inline void ADD_TO_VEC_int(T &n, vector<T> &vec){vec.clear(); cin >> n; for(int i = 0; i < n; i ++){T x; cin >> x, vec.PB(x);}}
template<typename T> inline pair<T, T> MaxInVector_ll(vector<T> vec){T MaxVal = -LNF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_ll(vector<T> vec){T MinVal = LNF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<T, T> MaxInVector_int(vector<T> vec){T MaxVal = -INF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_int(vector<T> vec){T MinVal = INF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<map<T, T>, vector<T> > DIV(T n){T nn = n;map<T, T> cnt;vector<T> div;for(ll i = 2; i * i <= nn; i ++){while(n % i == 0){if(!cnt[i]) div.push_back(i);cnt[i] ++;n /= i;}}if(n != 1){if(!cnt[n]) div.push_back(n);cnt[n] ++;n /= n;}return make_pair(cnt, div);}
namespace Solution_In_Codeforces{
inline void solve();
namespace N_cass {
int Main(){ int cass; for ( cin >> cass; cass; cass -- ) { solve();} return 0;};
}
namespace One_cass {
int Main(){ solve(); return 0;};
}
}
inline void Solution_In_Codeforces::solve(){};
const int N = 5e4 + 10;
class KMP_node{
private:
string a, b;
int nxt[N];
public:
inline KMP_node ( string aa, string bb) { a = aa; b = bb; }
inline void Get_Next ( ) {
int j = -1;
for ( int i = 0; i < N; i ++ ) nxt[i] = -1;
for ( int i = 0; i + 1 < a.size(); i ++ ) {
while ( j >= 0 && a[j + 1] != a[i + 1] ) j = nxt[j];
if ( a[j + 1] == a[i + 1] ) j ++;
nxt[i + 1] = j;
}
}
inline void KMP ( ) {
int j = -1, res = 0;
for ( int i = -1; i + 1 < b.size(); i ++ ) {
while ( j >= 0 && a[j + 1] != b[i + 1] ) j = nxt[j];
if ( a[j + 1] == b[i + 1] ) j ++;
if ( i + 1 == b.size() - 1 ) res = j;
if ( j == a.size() - 1 ) j = nxt[j];
}
if ( res == -1 ) cout << "0" << endl;
else cout << a.substr(0, res + 1) << " " << res + 1 << endl;
}
};
string sa, sb;
CHIVAS_{IOS;
while ( cin >> sa >> sb ) {
KMP_node kmp = KMP_node(sa, sb);
kmp.Get_Next();
kmp.KMP();
}
_REGAL;
}
int main(){
#ifndef ONLINE_JUDGE
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
Main();
#ifndef ONLINE_JUDGE
cerr << "\033[1m\033[31m" << "\n\n===============================\n" << "|| Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s. ||\n" << "===============================" << "\033[0m";
#endif
exit(0);
}
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# HDU3336_CountTheString
# 🔗
https://acm.hdu.edu.cn/showproblem.php?pid=3336
# 💡
开始的时候想到，如果枚举出来前缀，然后用KMP搜一遍
时间O(n^2)，肯定会超时
那么想到KMP是使用nxt数组进行回溯到重复的公共前后缀
那么我们可以发现每一次回溯都是因为有一个相同的串（而且如果前面顶到头，则就与前缀有关了）
那么我们只需要每个位置统计一下回溯的数量即可
不断回溯时间过长，可以使nxt[i]递推出dp[i] = dp[nxt[i]] + 1
# ✅
/*
________ _ ________ _
/ ______| | | | __ | | |
/ / | | | |__| | | |
| | | |___ _ _ _ ___ _ _____ | ___| ______ _____ ___ _ | |
| | | __ \ |_| | | | | | _\| | | ____| | |\ \ | __ | | _ | | _\| | | |
| | | | \ | _ | | | | | | \ | | \___ | | \ \ | |_/ _| | |_| | | | \ | | |
\ \______ | | | | | | \ |_| / | |_/ | ___/ | | | \ \ | /_ \__ | | |_/ | | |
Author : \________| |_| |_| |_| \___/ |___/|_| |_____| _________|__| \__\ |______| | | |___/|_| |_|
____| |
\_____/
*/
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <utility>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define EPS 1e-6
#define PI acos(-1.0)
#define INF 0x7FFFFFFF
#define ll long long
#define ull unsigned long long
#define INT __int128
#define LOWBIT(x) ((x) & (-x))
#define LOWBD(a, x) lower_bound(a.begin(), a.end(), x) - a.begin()
#define UPPBD(a, x) upper_bound(a.begin(), a.end(), x) - a.begin()
#define TEST(a) cout << "---------" << a << "---------" << endl
#define CHIVAS_ inline int Main()
#define _REGAL return 0;
#define SP system("pause")
#define IOS ios::sync_with_stdio(false)
//#define map unordered_map
#define pii pair<int, int>
#define pll pair<ll, ll>
#define PB(x) push_back(x)
#define ALL(a) a.begin(),a.end()
#define MEM(a, b) memset(a, b, sizeof(a))
#define EACH_CASE(cass) for (cass = inputInt(); cass; cass--)
#define LS l, mid, rt << 1
#define RS mid + 1, r, rt << 1 | 1
#define GETMID (l + r) >> 1
using namespace std;
inline int inputInt(){int X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1);}
inline void outInt(int X){if(X<0) {putchar('-'); X=~(X-1);}int s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
inline ll inputLL(){ll X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1); }
inline void outLL(ll X){if(X<0) {putchar('-'); X=~(X-1);}ll s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
template<typename T> inline T MAX(T a, T b){return a > b? a : b;}
template<typename T> inline T MIN(T a, T b){return a > b? b : a;}
template<typename T> inline void SWAP(T &a, T &b){T tp = a; a = b; b = tp;}
template<typename T> inline T GCD(T a, T b){return b > 0? GCD(b, a % b) : a;}
template<typename T> inline void ADD_TO_VEC_int(T &n, vector<T> &vec){vec.clear(); cin >> n; for(int i = 0; i < n; i ++){T x; cin >> x, vec.PB(x);}}
template<typename T> inline pair<T, T> MaxInVector_ll(vector<T> vec){T MaxVal = -LNF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_ll(vector<T> vec){T MinVal = LNF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<T, T> MaxInVector_int(vector<T> vec){T MaxVal = -INF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_int(vector<T> vec){T MinVal = INF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<map<T, T>, vector<T> > DIV(T n){T nn = n;map<T, T> cnt;vector<T> div;for(ll i = 2; i * i <= nn; i ++){while(n % i == 0){if(!cnt[i]) div.push_back(i);cnt[i] ++;n /= i;}}if(n != 1){if(!cnt[n]) div.push_back(n);cnt[n] ++;n /= n;}return make_pair(cnt, div);}
namespace Solution_In_Codeforces{
inline void solve();
namespace N_cass {
int Main(){ int cass; for ( cin >> cass; cass; cass -- ) { solve();} return 0;};
}
namespace One_cass {
int Main(){ solve(); return 0;};
}
}
const int mod = 1e4 + 7;
const int N = 2e5 + 10;
class KMP_node{
private:
string a, b;
int nxt[N], dp[N];
public:
inline KMP_node ( string aa, string bb ) { a = aa, b = bb; }
inline void Get_Next ( ) {
int j = -1;
for ( int i = 0; i < b.size(); i ++ ) nxt[i] = -1, dp[i] = 0;
for ( int i = 0; i + 1 < b.size(); i ++ ) {
while ( j >= 0 && b[j + 1] != b[i + 1] ) j = nxt[j];
if ( b[j + 1] == b[i + 1] ) j ++;
nxt[i + 1] = j;
}
}
inline int Work ( ) { // 既然每次回溯都证明有一个公共串（也就是有一个相等的），回溯太慢，我们用nxt递推
int res = 0;
for ( int i = 0; i < b.size(); i ++ ) {
dp[i] = dp[nxt[i]] + 1;
res = (res + dp[i]) % mod;
}
return res;
}
};
inline void Solution_In_Codeforces::solve(){
int n; cin >> n; string s; cin >> s;
KMP_node kmp = KMP_node("", s);
kmp.Get_Next();
cout << kmp.Work() << endl;
}
CHIVAS_{IOS;
Solution_In_Codeforces::N_cass::Main();
_REGAL;
}
int main(){
#ifndef ONLINE_JUDGE
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
Main();
#ifndef ONLINE_JUDGE
cerr << "\033[1m\033[31m" << "\n\n===============================\n" << "|| Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s. ||\n" << "===============================" << "\033[0m";
#endif
exit(0);
}
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# HDU5763_AnotherMeaning
# 🔗
https://acm.hdu.edu.cn/showproblem.php?pid=5763
# 💡
在计算时我们发现这是一个方案数递推
那么可以得到，这道题可以使用dp汇聚方案
a串在每个点是否可以表示为一个 * 取决于这一点是否以b串结尾
那么就有一线性递推式：若mark[i] = 1, dp[i] = dp[i - 1] + dp[i - b.size()]
使用kmp不裁剪拼接一下
# ✅
/*
________ _ ________ _
/ ______| | | | __ | | |
/ / | | | |__| | | |
| | | |___ _ _ _ ___ _ _____ | ___| ______ _____ ___ _ | |
| | | __ \ |_| | | | | | _\| | | ____| | |\ \ | __ | | _ | | _\| | | |
| | | | \ | _ | | | | | | \ | | \___ | | \ \ | |_/ _| | |_| | | | \ | | |
\ \______ | | | | | | \ |_| / | |_/ | ___/ | | | \ \ | /_ \__ | | |_/ | | |
Author : \________| |_| |_| |_| \___/ |___/|_| |_____| _________|__| \__\ |______| | | |___/|_| |_|
____| |
\_____/
*/
#include <unordered_map>
#include <algorithm>
#include <iostream>
#include <cstring>
#include <utility>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define EPS 1e-6
#define PI acos(-1.0)
#define INF 0x7FFFFFFF
#define ll long long
#define ull unsigned long long
#define INT __int128
#define LOWBIT(x) ((x) & (-x))
#define LOWBD(a, x) lower_bound(a.begin(), a.end(), x) - a.begin()
#define UPPBD(a, x) upper_bound(a.begin(), a.end(), x) - a.begin()
#define TEST(a) cout << "---------" << a << "---------" << endl
#define CHIVAS_ inline int MAIN()
#define _REGAL return 0;
#define SP system("pause")
#define IOS ios::sync_with_stdio(false)
//#define map unordered_map
#define pbb pair<bool, bool>
#define pii pair<int, int>
#define pll pair<ll, ll>
#define PB(x) push_back(x)
#define ALL(a) a.begin(),a.end()
#define MEM(a, b) memset(a, b, sizeof(a))
#define EACH_CASE(cass) for ( int cass = inputInt(); cass; cass--)
#define LS l, mid, rt << 1
#define RS mid + 1, r, rt << 1 | 1
#define GETMID (l + r) >> 1
using namespace std;
inline int inputInt(){int X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1);}
inline void outInt(int X){if(X<0) {putchar('-'); X=~(X-1);}int s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
inline ll inputLL(){ll X=0; bool flag=1; char ch=getchar();while(ch<'0'||ch>'9') {if(ch=='-') flag=0; ch=getchar();}while(ch>='0'&&ch<='9') {X=(X<<1)+(X<<3)+ch-'0'; ch=getchar();}if(flag) return X;return ~(X-1); }
inline void outLL(ll X){if(X<0) {putchar('-'); X=~(X-1);}ll s[20],top=0;while(X) {s[++top]=X%10; X/=10;}if(!top) s[++top]=0;while(top) putchar(s[top--]+'0');}
template<typename T> inline T MAX(T a, T b){return a > b? a : b;}
template<typename T> inline T MIN(T a, T b){return a > b? b : a;}
template<typename T> inline void SWAP(T &a, T &b){T tp = a; a = b; b = tp;}
template<typename T> inline T GCD(T a, T b){return b > 0? GCD(b, a % b) : a;}
template<typename T> inline void ADD_TO_VEC_int(T &n, vector<T> &vec){vec.clear(); cin >> n; for(int i = 0; i < n; i ++){T x; cin >> x, vec.PB(x);}}
template<typename T> inline pair<T, T> MaxInVector_ll(vector<T> vec){T MaxVal = -LNF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_ll(vector<T> vec){T MinVal = LNF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<T, T> MaxInVector_int(vector<T> vec){T MaxVal = -INF, MaxId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MaxVal < vec[i]) MaxVal = vec[i], MaxId = i; return make_pair(MaxVal, MaxId);}
template<typename T> inline pair<T, T> MinInVector_int(vector<T> vec){T MinVal = INF, MinId = 0;for(int i = 0; i < (int)vec.size(); i ++) if(MinVal > vec[i]) MinVal = vec[i], MinId = i; return make_pair(MinVal, MinId);}
template<typename T> inline pair<map<T, T>, vector<T> > DIV(T n){T nn = n;map<T, T> cnt;vector<T> div;for(ll i = 2; i * i <= nn; i ++){while(n % i == 0){if(!cnt[i]) div.push_back(i);cnt[i] ++;n /= i;}}if(n != 1){if(!cnt[n]) div.push_back(n);cnt[n] ++;n /= n;}return make_pair(cnt, div);}
namespace Solution_In_Codeforces{
inline void solve();
namespace N_cass {
void Main(){ int cass; for ( cin >> cass; cass; cass -- ) { solve();} };
}
namespace One_cass {
void Main(){ solve(); };
}
}
inline void Solution_In_Codeforces::solve() {}
// ============================================================= BeginCode ==========================================================================================
const ll mod = 1e9 + 7;
const ll N = 100005;
int nxt[N];
ll mark[N], dp[N]; // 标记， 递推
ll CasId = 0;
inline void Get_Next ( string s ) {
nxt[0] = -1;
for ( ll i = 0, j = -1; i < s.size(); i ++ ) {
while ( j >= 0 && s[i + 1] != s[j + 1] ) j = nxt[j];
if ( s[i + 1] == s[j + 1] ) j ++;
nxt[i + 1] = j;
}
}
inline void KMP ( string a, string b ) {
MEM(mark, 0);
Get_Next ( b );
for ( ll i = -1, j = -1; i + 1 < a.size(); i ++ ) {
while ( j >= 0 && a[i + 1] != b[j + 1] ) j = nxt[j];
if ( a[i + 1] == b[j + 1] ) j ++;
if ( j + 1 == b.size() ) mark[i + 1] = 1, j = nxt[j]; // 若凑成了就在这个位置标记一下
}
}
CHIVAS_{
EACH_CASE( cass ) {
string a, b; cin >> a >> b;
cout << "Case #" << ++CasId << ": ";
KMP(a, b);
//for ( int i = 0; i < a.size(); i ++ ) cout << mark[i] << " "; cout << endl;
dp[0] = 1;
for ( int i = 1; i <= a.size(); i ++ ) {
dp[i] = dp[i - 1];
if ( mark[i - 1] ) dp[i] = (dp[i] + dp[i - b.size()]) % mod;
}cout << dp[a.size()] << endl;
}
_REGAL;
}
// ============================================================= EndCode ==========================================================================================
int main(){
#ifndef ONLINE_JUDGE
freopen("in.in", "r", stdin);
freopen("out.out", "w", stdout);
#endif
MAIN();
#ifndef ONLINE_JUDGE
cerr << "\033[1m\033[31m\n"
<< "\n\n===============================\n"
<< "|| Time elapsed: " << 1.0 * clock() / CLOCKS_PER_SEC << " s. ||\n"
<< "==============================="
<< "\033[0m";
#endif
exit(0);
}
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# PTA_好中缀
# 🔗
https://pintia.cn/problem-sets/1384757951243542528/problems/1384758301778305035
# 💡
是一个单一对next数组的应用过程
# ✅
#pragma GCC optimize(3,"Ofast","inline")
#include <algorithm>
#include <iostream>
#include <cstring>
#include <string>
#include <vector>
#include <cstdio>
#include <stack>
#include <queue>
#include <cmath>
#include <map>
#include <set>
#define G 10.0
#define LNF 1e18
#define eps 1e-6
#define PI acos(-1.0)
#define ll long long
#define INF 0x7FFFFFFF
#define Regal exit(0)
#define Chivas int main()
#define pb(x) push_back(x)
#define SP system("pause")
#define Max(a,b) ((a)>(b)?(a):(b))
#define Min(a,b) ((a)<(b)?(a):(b))
#define IOS ios::sync_with_stdio(false)
#define mm(a, b) memset(a, b, sizeof(a))
#define each_cass(cass) for (cin>>cass; cass; cass--)
#define test(a) cout << "---------" << a << "---------" << '\n'
using namespace std;
const int maxn = 100005;
int Next[maxn];
int ans[maxn];
string s;
inline void get_next(){
int i = 0;
int k = -1;
Next[0] = -1;
int len = s.size();
while(i < len){
if(k == -1 || s[i] == s[k]) Next[++i] = ++k;
else k = Next[k];
}
}
Chivas{
IOS;
getline(cin,s);
get_next();
int len = s.size();
int len_ans = 0;
int j = Next[s.size()];
while(j > 0){
ans[len_ans ++] = j;
j = Next[j];
}
sort(ans, ans + len_ans, greater<int>());
if(s.size() == 1){
cout << "1" << endl;
Regal;
}
int res = len - ans[1] * 2;
if(res < 0) res = 0;
printf("%d", res);
Regal;
}
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